Question

a cube of lead with edges measuring 6 cm each is melted and formed into 27 equal cubes what will be the length of the edges of the new cubes........ please answer this question and you will get hundred points ​

Answer 1

Step-by-step explanation:

volume of starting cube = 6×6×6 cm^3

let x be sides of new cubes,

volume of each new cube = x³

evaluating volumes, we get

6×6×6 = 27× x³

x³ = 8

x=2

so, sode of new cubes are 2 cm each

Answer 2

$\huge{\underline{\mathbb{\red{Solution}}}}$

volume of starting cube = 6 × 6 × 6 CM cube

$\huge{\underline{\mathbb{\pink{Let,}}}}$

the sides of new Cube be X

$= > volume = {x}^{3}$

Putting values we get,

$= > 6 \times 6 \times 6 = 27 \times {x}^{3}$

$= > {x}^{3} = 8$

$= > x = 2$

______________________________________

$\huge{\underline{\mathbb{\pink{Thankyou}}}}$