Question

a cube of lead with edges measuring 6 cm each is melted and formed into 27 equal cubes what will be the length of the edges of the new cubes

Answer 1

here, we must equate volumes,

volume of starting cube = 6×6×6 cm^3

let x be sides of new cubes,

volume of each new cube = x^3

evaluating volumes, we get

6×6×6 = 27× x^3
x^3 = 8
x=2

so, sode of new cubes are 2 cm each

Answer 2

Given,

Edge of the lead cube = 6 cm

The cube is melted into 27 equal cubes.

To Find,

Edge of the new cube.

Solution,

Since the same cube is melted into 27 equal cubes So, the volume will remain the same

The volume of the big cube = 27*volume of the new cube

Let the edge of the new cube be x cm

So,

6*6*6 = 27*x³

x³ = 8

x = ∛8 = 2 cm
Hence, the edge of the new cube is 2 cm.