a cube of lead with edges measuring 6 cm each is melted and formed into 27 equal cubes what will be the length of the edges of the new cubes
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Answered by
166
here, we must equate volumes,
volume of starting cube = 6×6×6 cm^3
let x be sides of new cubes,
volume of each new cube = x^3
evaluating volumes, we get
6×6×6 = 27× x^3
x^3 = 8
x=2
so, sode of new cubes are 2 cm each
volume of starting cube = 6×6×6 cm^3
let x be sides of new cubes,
volume of each new cube = x^3
evaluating volumes, we get
6×6×6 = 27× x^3
x^3 = 8
x=2
so, sode of new cubes are 2 cm each
anjali214:
please explain how did 6×6×6 became 27
there are 27 new cubes
so, volume of old cube (6×6×6) became equal to volune of all new cubes (27× x × x × x)
got it?
ya
then, please mark it brainliest, if you understood the solution
Right answer great job
Answered by
7
Given,
Edge of the lead cube = 6 cm
The cube is melted into 27 equal cubes.
To Find,
Edge of the new cube.
Solution,
Since the same cube is melted into 27 equal cubes So, the volume will remain the same
The volume of the big cube = 27*volume of the new cube
Let the edge of the new cube be x cm
So,
6*6*6 = 27*x³
x³ = 8
x = ∛8 = 2 cm
Hence, the edge of the new cube is 2 cm.
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