A cube of lead with edges measuring 6 cm each is melted and formed into 27 equal cubes. What will be the length of the edges of the new cubes?
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find the vol of bigger cube and than divide it with 27 then the vol of 1 cube will come and than find the edge of the cube
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volume of cube melted= 27×volume of new cube
A^3=27×a^3
6×6×6=27×a^3
a^3={6×6×6}÷27
a^3=8
a=2cm , where a is edge of new cube
A^3=27×a^3
6×6×6=27×a^3
a^3={6×6×6}÷27
a^3=8
a=2cm , where a is edge of new cube
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