Question

a cube of mass 2 kg with each side of 1cm is lying on the table find the pressure exerted by the block on the table

Answer 1

P=Thrust/area
Now given,m=2kg & side=1cm
thus thrust=ma=2x9.8=19.6N
area=(side)²=1²=1
P=19.6/1=19.6

Answer 2

The pressure exerted by the block on the table is 196000 N/m².

Here, according to the given information, we are given that,

A cube is given which has a mass of 2 kg. It has also been told that each side of the cube has a measurement of 1 cm. We need to find the pressure that has been exerted by the block on the table.

Now, in order to find the pressure exerted, we need to calculate the thrust exerted. Now, the thrust is found out by multiplying the mass of the block with the acceleration due to gravity.

Let us suppose that the acceleration due to gravity is 9.8 m/s.

Then, the thrust exerted = $2(9.8) = 19.6 kgms^{-1}$

Now, we know that, pressure is thrust per unit area.

Then, by putting the values in the above formula, we get,

Pressure = $\frac{19.6}{0.0001}$ = 196000 N/m², where area of the cube was found out by squaring the measurement of one side of the cube that is

$(0.01)^{2} = 0.0001$ m².

Hence, the pressure exerted by the block on the table is 196000 N/m².

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