Question

A cube of mass 20 kg placed on a horizontal surface exert 200 PA on the surface,then find area of base of cube

Answer 1

Force app = Normal force on surface = m x a = 200 N (g = 10m/s^-2)

Pressure = Force / Area

=> 200N/Area = 200 Pa

=> Area = 200/200 = 1 m^2.

Clear?

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Good Luck!

Answer 2

Answer:

1$m^2$

Explanation:

Force app = Normal force on surface = m x a = 200 N (g = 10m/s^-2)

Pressure = Force / Area

=> 200N/Area = 200 Pa

=> Area = 200/200 = 1 m^2.