A cube of side 0.2 m rests on the floors.
Given that the mass of the cube is 50 kg, the pressure exerted by the cube is ________. ( Take good = 10 N kg -¹ )
Options:
A) 25 N -²
B) 250 N m -²
C) 1250 N m -²
D) 12500 N m -²
Answers
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here is your answer hope u like it
P = F/A
A = 0.2 *0.2
F = mg = 50 × 10
P = 500/0.04
P = 12500 pa
P = F/A
A = 0.2 *0.2
F = mg = 50 × 10
P = 500/0.04
P = 12500 pa
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arun13rathor:
Thank u
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