A cube of side 0.4m rests on the floor as shown given that the cube has a mass of 200kg the pressure exerted by the cube on the floor is ( take g = 10 N kg)
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1. Mass of cube is given by 200 kg
g that is gravity is given by 10 Newton
Force = mass x gravity
= 200 x 10
F = 2000 N
The side length of a cube is 0.4 m
Surface area of one face of a cube can be taken as side x side
Area of one face of a cube can be taken as
0.4 x 0.4 = 0.16 m^2
Pressure = force / area
= 2000 / 0.16
= 12,500 N/m^2
Now the pressure exerted by the cube on the floor is 12,500 N/m^2
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side length of cube = 0.4 m
so, surface area of cube = side length²
= 0.4 × 0.4 = 0.16 m²
mass of cube = 200 kg
so, weight of cube = Mass of cube × g
= 200kg × 10 m/s² = 2000 N
now, pressure = weight/surface area of cube
= 2000/0.16
= 2000 × 100/16
= 2000 × 25/4
= 500 × 25
= 12500 N/m²
so, surface area of cube = side length²
= 0.4 × 0.4 = 0.16 m²
mass of cube = 200 kg
so, weight of cube = Mass of cube × g
= 200kg × 10 m/s² = 2000 N
now, pressure = weight/surface area of cube
= 2000/0.16
= 2000 × 100/16
= 2000 × 25/4
= 500 × 25
= 12500 N/m²
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