a cube of side 10cm floats in a fluid of density 1.5 g/cc. find the density of cube . if 3m of its length is inside the fluid
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Explanation:
If water level rises by 2mm or 0.2cm in the cylindrical beaker of base area
1500
c
m
2
due to keeping of mass
m
on the floating cube then volume of water more displaced for this will be
V
=
1500
⋅
0.2
=
300
c
m
3
.
The mass of this water will represent the mass of
m
.Since weight of the mass
m
is the weight of the displaced water following the condition of floatation.
So mass of
m
= mass of
300
c
m
3
water=
300
⋅
1
g
=
300
g
(Considering density of water as
1
g
c
m
−
3
So
m
=
300
g
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