Question

A cube of side 20cm is floating on a liquid with 5cm of the cube outside the liquid. If the density of liquid is 0.8gm/c.c then the mass of the cube is

Answer 1

Answer:

The answer is 4.8kg

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Answer 2

300 grams.

Explanation:

Given that we have a cube floating in water with a specific amount of height outside the water.

The amount of height the body goes inside the water is directly proportional to the mass of the object .

The upward force acting on the body would be dependent on the volume submerged inside the water.

Let the volume submerged inside water be Vi.

In the question it is given that cube has a height 5 cm outisde water.

Total height of the cube is 20 cm so the hieght in the water is given by 15cm.

Area of the surface is 25 units.

So volume of the submerged part is ,

$V=25*15cm^{3}$

$V=375cm^{3}$

So the governing equations would be,

$pVg=mg\\ \\0.8*375*g=m*g\\\\m=375*0.8\\m=300gm$

Hence the mass of the cube is 300grams.