Question

A Cube of side 4 cm contains a sphere touching its side. Find the volume of the gap in between ?​

Answer 1

Answer:

volume of cube=4×4×4=64

as the sphere touches the side of the cube

dia=4

radius=2

volume f sphere=4/3Лr²=33.51cm³

hence volume of the gap=v of cube-v of sphere

64-33.51=30.49cm³

Step-by-step explanation:

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Answer 2

Answer:

radius of sphere = half of side of Cube = 2cm

volume of gap = (volume of cube) -( volume of sphere)

$(4 \times 4 \times 4 )- ( \frac{4}{3} \times \frac{22}{7} \times {2}^{3} ) \\ 64 - 33.6 \\ 30.4 {cm}^{3} (approx)$