A cube of side a has charge q located at one of its corners .Calcilate the flux of electric field through shaded side
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If charge is at the corner then it will be shared by 8 cubes.
Charge for 1 cube = q/8
Now in any given cube it is touching 3 9f its faces. So the area vector of that side and the electric field vector will be perpendicular. So flux through those 3 sides will be 0.
Equal amount of flux will flow from the other 3 sides.
So flux through 1 side = (q/8)/3 = q/24.
Hope that helps