A cube of side a units is vertically cut into two halves .what is the total surface area of each half?
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Answer:
TSA of the so formed cuboid is 4a²
Step-by-step explanation:
when the cube is cut vertically into 2 halves ,
it's l = a , b = a & h = a/2
TSA of 1 cuboid = 2(lb+lh+bh)
= 2(a×a + a×a/2 + a×a/2 )
= 2(a² + a²/2 + a²/2 )
= 2(4a²/2)
= 4a²
∴ TSA of the 2 cuboids formed = 2×4a²
= 8a²
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