Physics, asked by mahivarshini506, 1 year ago

A cube of side b has a charge q at each of its vertices. The
electric field due to this charge distribution at the centre of
this cube will be times
1/4pi epsilon not.
a) q/b^2
(b)q/2b^2
(c)32q/b^2
(d) zero

Answers

Answered by sahilcs1111
3

The Field Should Be Zero as each field from a charge apposed each other in direction.

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