A cube of side length 8 cmn is taken and small cubes of 2 cm length are cut along all the eight corners
of the cube. By what percentage does the total surface area of the cube changes?
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Answer:
Side (a) of cube =8 cm
Volume of cube = (a)3 = 512 cm
Let the side of the smaller cube be a1.
volume of smaller cube
(2)3=8
total no. of cubes= 512/8=64
total surface of smaller cube=6(edge)2
6(2)2=6×4=(24 cm)2
total surface area=24×64=1536cm3
percent = 1536/512×100=300%
NOTE=Not sure about percentage
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