A cube of side length l and coefficient of linear expansion alpha floating in a liquid of volume expansion gama when temperature increases the depth up to which the cube is submerged in the liquid remains same find the relation between. alpha and gama
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Explanation:
Solution :
Befor heating
Mg=Fb,Mg=V1ρ1g=Axρ1g ……..(1)
After heating Mg=F1b,Mg=V1ρ11g ……(2)
Equating (1) & (2)Axρ11g
Aρ1g=A(l+βΔt)ρ11+γDetlatg
1+γΔt=1+βΔt,γ=β∴γ=2α
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