A cube of side 'm', a cuboidal cross section 'm/3' * 'm/5' is removed making a hole. Find the percentage change in the TSA of the cube
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Answer:
182
Step-by-step explanation:
Given, cross - sectional area of a square =4cm
2
l=5cm
Surface area of a cube =6l
2
=6(5)
2
=150cm
2
Total surface area of the cube =150−2×4 =142cm
2
Area of the four walls of the hole made parallel to the side of the cube
=4×2×5
=40cm
2
Total surface area of the body formed =(142+40)cm
2
=182cm
2
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