Physics, asked by beastgalaxygaming, 21 days ago

A cube of side x rests on the floor given that the pressure exerted by this cube on the floor is P, what is the pressure exerted by another cube of the same material of side 4x?
Take g=10N/Kg

Answers

Answered by poojaluv25
1

Answer:

4P

Explanation:

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Answered by dsk75
4

Answer:

4P

Explanation:

FOR THE SMALLER CUBE

let density of cube = d

volume of cube = x³

base area = x²

mass = density × volume = dx³

force exerted = weight of cube = mass × g

                       = dx³g

presssure exerted = (force exerted)/(basal area)

                         P   = (dx³g)/x²

                 ⇒     P = dxg ----- (1)

FOR THE BIGGER CUBE

∵ big cube is made up of same material as small cube

density = d

volume = (4x)³ = 64x³

base area = (4x)² = 16x²

mass = density × volume = 64dx³

force exerted =weight of cube = mass × g

                       = 64dx³g

presssure exerted = (force exerted)/(basal area)

                              = (64dx³g)/16x²

                              =  4dxg

                              = 4P (from equation 1)

∴ pressure exerted by another cube of the same material was 4P

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