a cube of volume 6ml is immersed fully in water. calculate the upward force experienced by the water. density of water is 1000kg/m cube, g =9.8m/s Sq.
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We're asked to find the volume occupied by
1
molecule
of
H
2
O
.
We can find this through a few steps:
Convert molecules to moles via Avogadro's number
Convert moles to grams via molar mass
Convert grams to cubic centimeters (milliliters) via density
Step 1:
We'll first convert the one molecule of water to moles, using Avogadro's number:
1
molecule H
2
O
(
1
l
mol H
2
O
6.022
×
10
23
molecules H
2
O
)
=
1.66
×
10
−
24
mol H
2
O
Step 2:
Now, using the molar mass of water (
18.02
g/mol
), we'll calculate the number of grams:
1.66
×
10
−
24
mol H
2
O
(
18.02
l
g H
2
O
1
mol H
2
O
)
=
2.99
×
10
−
23
g H
2
O
Step 3:
Finally, knowing that
1
g
water occupies a volume of
1
cm
3
(or
1
mL
, which is more conventional for liquids), we can calculate the volume occupied by one molecules of water:
2.99
×
10
−
23
g H
2
O
(
1
l
mL
1
g H
2
O
)
=
2.99
×
10
−
23
mL H2O
Hope it helps you.
1
molecule
of
H
2
O
.
We can find this through a few steps:
Convert molecules to moles via Avogadro's number
Convert moles to grams via molar mass
Convert grams to cubic centimeters (milliliters) via density
Step 1:
We'll first convert the one molecule of water to moles, using Avogadro's number:
1
molecule H
2
O
(
1
l
mol H
2
O
6.022
×
10
23
molecules H
2
O
)
=
1.66
×
10
−
24
mol H
2
O
Step 2:
Now, using the molar mass of water (
18.02
g/mol
), we'll calculate the number of grams:
1.66
×
10
−
24
mol H
2
O
(
18.02
l
g H
2
O
1
mol H
2
O
)
=
2.99
×
10
−
23
g H
2
O
Step 3:
Finally, knowing that
1
g
water occupies a volume of
1
cm
3
(or
1
mL
, which is more conventional for liquids), we can calculate the volume occupied by one molecules of water:
2.99
×
10
−
23
g H
2
O
(
1
l
mL
1
g H
2
O
)
=
2.99
×
10
−
23
mL H2O
Hope it helps you.
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