Question

A cube of wood of volume 0.2 m' and density
600 kg mis placed in a liquid of density
800 kg m.
(a) What fraction of the volume of the wood be
immersed in the liquid?

(b) What force must be applied to the cube so that
the top surface of the cube is on the same level
as the liquid surface?

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Answer 1

Answer:

Volume of wood = 0.2 m3

Density of wood = 600 kg/m3

Density of liquid = 800 kg/m3

Answer 2

Answer:

volume of wood = 0.2 m3

Density of wood = 600 kg / m3

Density of liquid = 800 kg / m3