Question

a cube plus b cube + A + B factorise​

Answer 1

use identity:a^3+b^3=a+b(a^2-ab+b^2)

put this identity in the problem

a+b(a^2-ab+b^2)+a+b

factor out a+b as common;

a+b{(a^2-ab+b^2)+1}

a+b(a^2-ab+b^2+1)

hope it help plz like

Answer 2

The factorization of the given expression is $(a+b)(a^2+b^2-ab+1)$.

Explanation:

The given expression : $a^3+b^3+a+b$

Using identity : $x^3+y^3=(x+y)(x^2+y^2-xy)$

The above expression will become :

$a^3+b^3+a+b = (a+b)(a^2+b^2-ab)+a+b$

Taking (a+b) out as common , we get

$=(a+b)(a^2+b^2-ab+1)$

Hence, the factorization of the given expression is $(a+b)(a^2+b^2-ab+1)$.

# Learn more :

Prove that (a+b)cube+(b+c)cube+(c+a)cube-3(a+b)×(b+c)×(c+a)=2(acube+bcube+ccube)

https://brainly.in/question/2420870