Question

A cube's volume increased by 10℅.how much percentage of surface area does it increase now

Answer 1

21%
Let the edge be 'x'
After increasing 10%= (10% of x) + x
T.S.A(Total surface area)=6 x² square square units[didn't get x power of 2]
                                     = 6 {(10/100 of x) + x}² 
                                     =6 (x/10 + x )²
                                     =6(11x/10)²
                                     =6 × 121x²/100
                                     = 726x²/100
                                     =7.26x²

7.26x² is the new TSA

Increase percent=Increase/Original Price ×100

Here, Increase= 7.26x²-6x²
                     =1.26x²
Increase percent=1.26x²/6x² ×100
                         =126/6
                         =21%

Sorry it is for edge increased by 10%

Answer 2

Step-by-step explanation:

I hope you can understand