Question

A cube that contains a wet concrete has a dimensions of 2 x 3 x 4 meters are
poured into another container having a width of 10 meter. Find the length and
height of the concrete formed if L = W

Answer 1

Given:

A cube that contains a wet concrete has a dimensions of 2 x 3 x 4 meters are  poured into another container having a width of 10 meter.

To Find:

Find the length and  height of the concrete formed if L = W.

Solution:

It is given that - a cube that contain a wet container has dimension of 2 x 3 x 4 meters.

therefore, Volume of wet concrete is -

$\[\begin{array}{*{20}{l}} {{V_1} = {\text{ }}L{\text{ }} \times {\text{ }}W{\text{ }} \times {\text{ }}H} \\ { = {\text{ }}2 \times 3 \times 4} \\ { = 24} \end{array}\]$

thus, volume of wet concrete is $24 m^{3}$.

Now, according to question a cube that contains a wet concrete has a dimensions of 2 x 3 x 4 meters are  poured into another container having a width of 10 meter.

let, length of another container be 'a' then L=W=a

so, Vol. of cube that contain wet concrete = Vol. of another container.

$\[\begin{gathered} 24{\text{ }} = a{\text{ }} \times 10{\text{ }} \times {\text{ }}a{\text{ }} \hfill \\ {a^2}{\text{ }} = 24 \div 10 \hfill \\ {\text{ }}a{\text{ }} = \sqrt {2.4} {\text{ }} \hfill \\ a{\text{ = 1}}{\text{.55 }} \hfill \\ \end{gathered} \]$

therefore, L=1.55 m .

Hence, length and height of the concrete formed is  1.55 m and 1.55 m respectively.