A cube with side length 10 cm is made up of metal (E= 25×10 N/m²) a horizontal shear force is 50,000 N is applied to the cube.
a) How far will the top of the cube move in the horizontal direction relative to the bottom of the cube? Dult.L = 0.02mm
b) What is the shear stress applied to the cube. stress = 5×10⁶N/m²
c) Calculate the shear strain on the cube.
Strain = 2×10‐⁴
Answers
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Answer:
b
Explanation:
hence modules of regidity is equal to 2×10^6Nm^_2
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