a cubes diagonal is 9√3 ,find its area
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Answered by
2
Hi ,
Let a , d are side and diagonal of a
cube ,
d = 9√3 ( given )
√3a = d
√3 a = 9√3
a = 9√3/√3
a = 9 units
Total surface area = 6a²
TSA = 6 × 9²
= 6 × 81
= 486 sq units
I hope this helps you.
: )
Let a , d are side and diagonal of a
cube ,
d = 9√3 ( given )
√3a = d
√3 a = 9√3
a = 9√3/√3
a = 9 units
Total surface area = 6a²
TSA = 6 × 9²
= 6 × 81
= 486 sq units
I hope this helps you.
: )
suzuya:
can we use Pythagorean theorum for this?
diagonal of a cubiod ( d ) = √( l² + b² + c²)
here in a cube l = b = h = a
d = √ ( a² + a² + a² )
d = √3a² = √3 × a
thank you ..that ll really help
yes , we use Phythagoruas Theorem
Answered by
3
Hi,
Please see the attached file!
Thanks
Please see the attached file!
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thank you so much
Welcome suzuya sister. :)
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