Physics, asked by Ankurs6523, 1 month ago

a cubic box of length 3cm is solidified in 5min in a sand casting if the box is melted and casted into spherical object then . calculate the time required to solidified the spherical object in the same atmospheric conditions.

Answers

Answered by jeevankishorbabu9985
1

Answer:

Given : A cubical box of length 3 cm is solidified in 5 min in a sand casting. box is melted and casted into spherical object

To Find : the time required to solidify the spherical object in the same atmospheric condition.

Solution:

Chvorinov’s Rule

Timing for solidification is ∝ ( V/A)²

V = Volume

A = Total Surface Area

Timing for solidification = C ( V/A)²

C is mold constant in Chvorinov's Rule

A cubical box of length 3 cm

Volume = 3 * 3 * 3 = 27 cm³

Surface Area = 6(3)² = 54 cm²

=> 5 = C ( 27/54)²

=> 5 = C (1/2)²

=> C = 20 min /cm²

For Sphere Volume = 27 cm³

(4/3)πR³ = 27

=> R³ = 27 * 3 / 4 π

=> R = 1.861

( V/A)² = ((4/3)πR³ / 4πR²)² = R²/9 = 0.3848

Time = 20 * 0.3848 = 7.7 min

7 mins 42 sec

Time required to solidify the spherical object in the same atmospheric condition. = 7 mins 42 sec

Explanation:

tq

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