a cubic box of length 3cm is solidified in 5min in a sand casting if the box is melted and casted into spherical object then . calculate the time required to solidified the spherical object in the same atmospheric conditions.
Answers
Answer:
Given : A cubical box of length 3 cm is solidified in 5 min in a sand casting. box is melted and casted into spherical object
To Find : the time required to solidify the spherical object in the same atmospheric condition.
Solution:
Chvorinov’s Rule
Timing for solidification is ∝ ( V/A)²
V = Volume
A = Total Surface Area
Timing for solidification = C ( V/A)²
C is mold constant in Chvorinov's Rule
A cubical box of length 3 cm
Volume = 3 * 3 * 3 = 27 cm³
Surface Area = 6(3)² = 54 cm²
=> 5 = C ( 27/54)²
=> 5 = C (1/2)²
=> C = 20 min /cm²
For Sphere Volume = 27 cm³
(4/3)πR³ = 27
=> R³ = 27 * 3 / 4 π
=> R = 1.861
( V/A)² = ((4/3)πR³ / 4πR²)² = R²/9 = 0.3848
Time = 20 * 0.3848 = 7.7 min
7 mins 42 sec
Time required to solidify the spherical object in the same atmospheric condition. = 7 mins 42 sec
Explanation:
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