Physics, asked by chauhanchestha710, 9 months ago

A cubic vessel (with face horizontal + vertical) contains an
ideal gas at NTP. The vessel is being carried by a rocket
which is moving at a speed of 500 m s⁻¹ in vertical direction.
The pressure of the gas inside the vessel as observed by
us on the ground
(a) remains the same because 500 ms⁻¹ is very much
smaller than vᵣₘₛ of the gas
(b) remains the same because motion of the vessel as a
whole does not affect the relative motion of the gas
molecules and the walls
(c) will increase by a factor equal to (v²ᵣₘₛ + (500)² ) / v²ᵣₘₛ
where vᵣₘₛ was the original mean square velocity of
the gas
(d) will be different on the top wall and bottom wall of the
vessel

Answers

Answered by Anonymous

Answer:

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