Question

a cubical block a of mass 10 kg and a block b of mass 2 kg are connected via string pulley system if one end of the string is pulled with a force 20 n as shown then the acceleration of wedge will be

Answer 1

Answer:

Since string is pulled by 100 N force. So tension in the string is 100 N F.B.D. of 10 kg block

100 - 10 g = 10 a

100 - 10 × 9.8 = 10 a

a=0.2m/s

2

Explanation:

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Answer 2

The acceleration of the wadge is 10 m/s²

Explanation:

Given that,

Mass of cubical block a= 10 kg

Mass of block b = 2 kg

Force = 20 N

The tension in the string will be equal to the applied force .

$T=F$

Put the value of F

$T=20 N$

Since, no other external force except the tension in the string is acting on the 2 kg block,

We need to calculate the acceleration of wedge

Using formula of Force

$F= ma$

Put the value into the formula

$20=2\times a$

$a=\dfrac{20}{2}$

[tex[a=10\ m/s^2[/tex]

Hence, The acceleration of the wadge is 10 m/s²

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Topic : acceleration

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