A cubical block of ice is completely immersed in water .what is the bouyant force acting on the block if the sidd of the block is 1 cm
Answers
Answered by
2
length of cube = 1cm
volume = 1×1×1 = 1cm³ = 10^-6 m³
when the cube is immersed in water, volume of water displaced = 1cm³ = 10^-6 m³
density of water = 1000kg/m³
weight of displaced water = density×volume×g = 1000×10^-6×9.8 = 9.8×10^-3 N
Since buoyant force is equal to the weight of water displaced, the buoyant force acting is 9.8×10^-3 N
volume = 1×1×1 = 1cm³ = 10^-6 m³
when the cube is immersed in water, volume of water displaced = 1cm³ = 10^-6 m³
density of water = 1000kg/m³
weight of displaced water = density×volume×g = 1000×10^-6×9.8 = 9.8×10^-3 N
Since buoyant force is equal to the weight of water displaced, the buoyant force acting is 9.8×10^-3 N
Answered by
0
When the cube is immersed in water
Volume of water displaced=1cube cm
Weight of displaced water=100×10^-6×9.8=9.8×10^-3N
Similar questions
Chemistry,
8 months ago
Science,
8 months ago
Physics,
1 year ago
Environmental Sciences,
1 year ago
Biology,
1 year ago