Question

A cubical block of side 10cm is surmointed by a hemisphere.What is the largest diameter that the hemisphere can have?Find the cost of painting the total surface area of solid so formed,at the rate of 5 rupee per 100 sq.cm.


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Answer 1

Answer:

Total surface area of the solid = Total surface area of the cube + curved surface area of the hemisphere - Area of the base of the hemisphere

= 6a2 + 2πr2 -πr2

= [ 6 x (10)2 + 2 x 3.14 x (5)2 - 3.14 x (5)2] cm2

= (600 +157 -78.5 ) cm2

= 678.5 cm2

Cost of painting = Rs 5 per 100 cm2

Therefore,

Cost of painting the solid = 678.5 x (5/100) = Rs. 33.90

Hence, the approximate cost of painting the solid so formed is Rs. 33.90.

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