A CUBICAL BLOCK OF SIDE 10CM IS SURMOUNTED BY A HEMISPHERE.WHAT IS THE LARGEST DIAMETER THAT THE HEMISPHERE CAN HAVE? FIND THE COST OF PAINTING THE TOTAL SURFACE AREA OF THE SOLID SO FORMED,AT THE RATE OF rs5 PER 100SQ.CM
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The largest diameter of he hemisphere = 10cm since it will be touching the sides of the cubical block.
Surface area = Surface area of the cube - area of circular part of the hemisphere + surface area of the hemisphere
= 10 x 10 x 6 - 22/7 x 5² + 2 x 22/7 x 5²
= 600 - 78 4/7 + 157 1/7
= 678 4/7 cm²
Cost of painting = (678 4/7 ÷ 100) x 5 = Rs. 33.93
Surface area = Surface area of the cube - area of circular part of the hemisphere + surface area of the hemisphere
= 10 x 10 x 6 - 22/7 x 5² + 2 x 22/7 x 5²
= 600 - 78 4/7 + 157 1/7
= 678 4/7 cm²
Cost of painting = (678 4/7 ÷ 100) x 5 = Rs. 33.93
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I may be correct answer
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