A cubical block of side 7 cm is surmounted by a hemisphere. What is the largest diameter
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Area of cube(excluding base)
A1=area of 4 walls+area of top
A1=4a^2+a^2
A1=5a^2
A1=5(7)^2
A1=5×49
A1=245cm^2
Let r be the largest radius of hemisphere from fig(2)
square ABCD in square of side 7cm
ln triangle ABC angle B=90
apply pythagoras th.
AC^2=AB^2+BC^2
(2r)^2=(7)^2+(7)^2
4r^2=98
r=√98/4
r=√24.5
Hence find required diameter
d=2r
d=2×√24.5
d=?
you find out its your job
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