A cubical block of side 7cm is surmounted by a hemisphere of maximum diameter.
Find the surface area and volume of the solid so obtained.
Answers
Answer:
Required Answer:
The greatest diameter=side of the cube=7cm.
The radius of the hemisphere =3.5cm.
Now,
The Surface Area of Solid=Surface Area of Cube - Surface Area of Base Hemisphere + Curve Surface Area of Hemisphere
Surface Area of Cube
=6×side
2
=6×7×7
=294sq cm
Surface Area of Base of Hemisphere is,
=πr
2
=
7
22
×3.5
2
=38.5cm
2
Curved Surface Area of Hemisphere is,
=2×38.5
=77sq cm
∴ total Surface Area is =294−38.5+77
=332.5sq cm.
Answer:
The greatest diameter=side of the cube=7cm.
The radius of the hemisphere =3.5cm.
Now,
The Surface Area of Solid=Surface Area of Cube - Surface Area of Base Hemisphere + Curve Surface Area of Hemisphere
Surface Area of Cube
=6×side
2
=6×7×7
=294sq cm
Surface Area of Base of Hemisphere is,
=πr
2
=
7
22
×3.5
2
=38.5cm
2
Curved Surface Area of Hemisphere is,
=2×38.5
=77sq cm
∴ total Surface Area is =294−38.5+77
=332.5sq cm.