a cubical block of side 7cm is surmounted by a hemisphere of the largest size . find the surface area of resulting solid
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Solution: The greatest diameter = side of the cube = 7 cm
Surface Area of Solid = Surface Area of Cube – Surface Area of Base of Hemisphere + Curved Surface Area of hemisphere
Surface Area of Cube = 6 x Side2
= 6 x 7 x 7 = 294 sq cm
Surface Area of Base of Hemisphere
=πr² =22/7×(3.5)²=38.5cm²
Curved Surface Area of Hemisphere = 2 x 38.5 = 77 sq cm
Total Surface Area = 294 – 38.5 + 77 = 332.5 sq cm
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Surface Area of Solid = Surface Area of Cube – Surface Area of Base of Hemisphere + Curved Surface Area of hemisphere
Surface Area of Cube = 6 x Side2
= 6 x 7 x 7 = 294 sq cm
Surface Area of Base of Hemisphere
=πr² =22/7×(3.5)²=38.5cm²
Curved Surface Area of Hemisphere = 2 x 38.5 = 77 sq cm
Total Surface Area = 294 – 38.5 + 77 = 332.5 sq cm
I hope this help ful for you.
please mark me as brainliest.☺️
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