a cubical block of side 7cm is surmounted by hemisphere. what is the greatest diameter the hemishpere can have? find surface area of solid
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the greatest diameter of hemisphere is 7cm.
total surface area = 6×(side)^2-πr^2+2πr^2
= 6×7×7+22÷7×7÷2×7÷2
= 294+154÷4
= (1176+154)÷4
= 1330÷4
= 332.5cm^2
total surface area = 6×(side)^2-πr^2+2πr^2
= 6×7×7+22÷7×7÷2×7÷2
= 294+154÷4
= (1176+154)÷4
= 1330÷4
= 332.5cm^2
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Answer:
332.5 cm²
Step-by-step explanation:
Side of the block = 7 cm
⇒ The greatest diameter of the hemisphere = 7 cm
Surface area of the solid
= [Total S.A. of the cubical block] + [S.A. of the hemisphere] – [Base area of the hemisphere]
= (6 × l2) + 2πr² – πr²
where l= 7cm r=7/2cm
(6×7²)+(2×22/7×7/2×7/2)-(22/7×7/2×7/2)cm²
=332.5 cm²
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