A cubical block of water is dipped completely in water. Each edge of the block is 1cm in length. Find the buoyant force acting on the block. (Pls tell how to solve)
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8
Buoyant force = Vdg
Here V = 1³ × 10^-6 m³
d = density of water = 1000Kg/m³
g = 10m/s²
B = 10^-6 * 1000 * 10 = 10^-2 N
Here V = 1³ × 10^-6 m³
d = density of water = 1000Kg/m³
g = 10m/s²
B = 10^-6 * 1000 * 10 = 10^-2 N
prakhal:
But answer is 10 ke power -2 N
Bro , 10^-2 this means 10 to the power -2
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3
the answer is in the attachment
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