A cubical block of weight 9.8 N with each side of 5 cm is lying on a table. The pressure exerted by the block on the table is
Answers
Answered by
37
Solution
Area of base= 5*5= 25cm^2
Force= 9.8N
pressure= force/ area
= 9.8/25= 0.392 Pascal.
_________
hope it helps,☺☺
Area of base= 5*5= 25cm^2
Force= 9.8N
pressure= force/ area
= 9.8/25= 0.392 Pascal.
_________
hope it helps,☺☺
Answered by
10
P=F/A
w =mg
9.8 = m*9.8
m=1kg
a = (5*10^-2)^2
P = mg/a
P= 1*9.8/25*10^-4 N/m
w =mg
9.8 = m*9.8
m=1kg
a = (5*10^-2)^2
P = mg/a
P= 1*9.8/25*10^-4 N/m
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