a cubical block of weight 9.8N with each side of 5 CM is laying on a table. the pressure exerted by the block on the table is
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Answer:
given,
F=9.8N
side=5cm
Pressure =force/area on which force acts
as we have to find the area so we have find the area only one side of the cube because only one side is in contact with it
area = side ^2
= 5^2 = 25
Pressure = 9.8/5 = 1.96
Explanation:
hope u understand it
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