Question

A cubical block of weight 9.8N with each side of 5 CM is lying on a table. the pressure exerted by the block on the table is

Answer 1

We know:-

Pressure=Force/Area

Calculate the area:-

Area of one side of the block=5cm*5cm

=25cm^2

So:-

Pressure=9.8/25Ncm^2

=0.392kPa

kPa is kilo Pascal and is 1 N/cm^2

So 0.392kPa=392Pa

Your answer:-392Pa

Hope it helps.

Answer 2

Area of one side of the block=5cm*5cm
=25cm^2
So:-
Pressure=9.8/25Ncm^2
=0.392kPa
kPa is kilo Pascal and is 1 N/cm^2
So 0.392kPa=392Pa


HOPE IT HELPS U ✌️✌️✌️