a cubical block of weight 9.8N with each side of 5cm is lying on table.the pressure exerted by the block on table is
Answers
Answered by
2
P = F/a
F = mg = 9.8*10 = 98N
a = side^2 = 5*10^-2 = 25*10^-4
P = 98/25*10^-4 = 4*10^4 N/m approx
F = mg = 9.8*10 = 98N
a = side^2 = 5*10^-2 = 25*10^-4
P = 98/25*10^-4 = 4*10^4 N/m approx
Similar questions