Question

A cubical block of wood is dipped completely in water. each edge of block is 1cm in length. find the buoyant force acting on the block.

Answer 1

the buoyant force acting on an object submerged in a liquid isF = ρgVwhereρ is the density of the liquid (here its water so ρ is known)g is the acceleration due to gravityandV is the volume of the submerged object or displaced liquid (= mass/volume)here,ρ = 1000 kg/m3g = 9.81 m/s2and V (for cube of 1 cm length) = 1 cm x 1cm x 1cm = 1cm3 = 10-6 m3thus, we haveF = 1000 x 9.81 x 10-6or buoyant force will beF = 0.00981 N