Question

A cubical block of wood of edge 0.2m weighing 6.4kgf floats on water. Find the depth of immersion. Given,density of water 1000kg/m^3.

Answer 1

Given:-

• Water density is 1000 kg/m^3 
• Edge of Cuboidal block = 0.2m
• Weight of Block = 4.6kgf

To Find:-

• Depth the block merged.

SoluTion:-

As,

$→\;{\sf{Edge×Depth×Density = Weight}}$

So,

$→\;{\sf{0.2m×0.2 m ×D × 1000 kg/m^3 = 6.4 kgf}}$

Where D is depth of immersion.

$→\;{\sf{D = 6.4kg/(1000x 0.2x 0.2) }}$

$→\;{\Large{\red{\bf{Depth = 0.16 m}}}}$

Hope It Helps You ✌️

Answer 2

Water density is 1000 kg/m^3

Edge of Cuboidal block = 0.2m

Weight of Block = 4.6kgf

To Find:-

Depth the block merged.

SoluTion:-

As,

→\;{\sf{Edge×Depth×Density = Weight}}→Edge×Depth×Density=Weight

So,

→\;{\sf{0.2m×0.2 m ×D × 1000 kg/m^3 = 6.4 kgf}}→0.2m×0.2m×D×1000kg/m

3

=6.4kgf

Where D is depth of immersion.

→\;{\sf{D = 6.4kg/(1000x 0.2x 0.2) }}→D=6.4kg/(1000x0.2x0.2)

→\;{\Large{\red{\bf{Depth = 0.16 m}}}}→Depth=0.16m