Question

a cubical block of wood of side 5 cm is kept on table top . the density of the block is 800 kg/m3 and g =9.8 m/s2v. find pressure exerted on wooden top

Answer 1

Answer:

Step-by-step explanation:

v=a^3=5^3=125 cm3

v=125/1000=0.125 m3

m=vd

=0.125*800

m=100 kg

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P=F/area

= mg/a2

=100*9.8/(0.05*0.05)

=980/0.0025

=392000 N/m2

F=mg

=