Question

A cubical block of wood of side 5cm5cm is placed on a table. Find the thrust by the block of wood on the table, if density of wood of 5g5g cm3cm3 and gg is 10m10m s2s2.

Answer 1

Answer:Density of wood, \rho=5gm^{-3}ρ=5gm

−3

g=10ms^{-2}g=10ms

−2

So, volume of cubical wood is V=5^3 cm^3=25\times10^{-6}m^3V=5

3

cm

3

=25×10

−6

m

3

Mass of the wood is m=\rho \times V=5\times 25\times 10^{-6}=125\times10^{-6}g=125\times 10^{-9}kgm=ρ×V=5×25×10

−6

=125×10

−6

g=125×10

−9

kg

Thrust force, T=m\times a=125\times10^{-9}\times10=1.25\times10^{-6}N.T=m×a=125×10

−9

×10=1.25×10

−6

N.

Explanation: