Question

A cubical block rests on a plane of u=root 3

Answer 1

Plz type the full question.

Answer 2

We know that

tanθ= coefficient of friction (u)  

By using the above data, we get the following result:

tanθ= Square root of 3 can be written as √3

Therefore tanθ= √3

As we need to find the angle, so move the tan θ to RHS. On moving it tanθ will be converted as reciprocal of tan°.

θ=tan^(-1)⁡√3

It implies that

θ = 60.

Hence, we come to the conclusion that the block rests on the plane of angle 60