Question

a cubical box has each edge 10cm and another cuboidal box is 12.5cm long,10cm wide and 8cm high ​

Answer 1

Step-by-step explanation:

HEY MATE ..

lateral surface area of the cube is larger by (400−360=40)cm2 (ii) Total surface area of cube = 6edge 2 =6(10) 2 =600 lateral surface area of cuboid =2(lb+bh+hl)2(12.5×10+10×8+8×12.5)=2(125+80+100)=610 So, the total surface area of cuboid is larger by (610−600=10) cm 2

Answer 2

Lateral surface area of cubical box = 4a2 = 4 x 102 = 400 cm^2

Lateral surface area of cuboidal box = 2h (l + b)

= 2 x 8(12.5 +10) = 16 X 22.5 = 360 cm^2

Thus, lateral surface area of cubical box is greater by

(400 cm2 - 360 cm2) = 40 cm^2

(ii) Total surface area of cubical box = 6a2 = 6 x 102 cm2 = 600 cm^2

Total surface area of cuboidal box = 2 (lb + bh + hl)

= 2(12.5 x 10 + 10 x 8 + 8 x 12.5)  

= 2(125 + 80 + 100)  = 2 x 305cm2  = 610 cm^2  

Thus, total surface area of cuboidal box is greater by (610 - 600) cm^2  

= 10 cm^2