Question

A cubical box has the length of 20cm and a cuboidal box has the length , breadth and height of 30cm,20cm, and 15 cm respectively . whose surface area is bigger and by how much?​

Answer 1

Step-by-step explanation:

Total Surface Area of the Rectangle

= 2× ( lb + bh + hl )

= 2× [ (30 × 20) + ( 20 × 15) + ( 30 × 15 ) ]cm^2

= 2× ( 600 + 300 + 450 ) cm^2

= 2× 1350cm^2

= 2700 cm^2

Total Surface Area of the square

= 6 × a^2 where a is the side of the square

= 6 × (20 cm)^2

= 6 × 400cm^2

= 2400 cm^2

Since the area of the rectangle is greater.

By how much = 2700cm^2 - 2400cm^2

= 300cm^2

Therefore the area of the rectangle is greater by 300cm^2

Thanks for reading this. Have a nice day

Answer 2

$cuboid \: has \: larger \: urface \: area$