Question

A cubical box of edge 10 cm is one-fourth filled with salt. The volume of salt in the box is-----
(i) 1000 cu. cm
(ii) 300 cu. cm
(iii) 250 cu. cm
(iv)250 sq. cm​

Answer 1

Given :

• Side of a Cube is 10 cm .

To Find :

• Volume of Salt in the box .

Solution :

Firstly we'll find the Volume of Box :

Using Formula :

$\longmapsto\tt\boxed{Volume\:of\:Cube={a}^{3}}$

Putting Values :

$\longmapsto\tt{{10}^{3}}$

$\longmapsto\tt\bf{1000\:{cm}^{3}}$

Now ,

As Given that one-fourth of box is filled with salt. So ,

$\longmapsto\tt{\dfrac{1}{{\cancel{4}}}\times{{\cancel{1000}}}}$

$\longmapsto\tt\bf{250\:{cm}^{3}}$

So , The Volume of Salt is 250 cm³ .

____________________

• Volume of Cube = a³
• Lateral Surface Area of Cube = 4a²
• Total Surface Area of Cube = 6a²
• Volume of Cuboid = l×b×h
• Lateral Surface Area of Cuboid = 2h (l+b)
• Surface Area of Cuboid = 2(lb+bh+hl)

____________________

Answer 2

Given :-

A cubical box of edge 10 cm is one-fourth filled with salt

To Find :-

Volume of salt

Solution :-

Here

Volume of salt = Volume of cube

Volume of cube = edge³

Volume = (10)³

Volume = (10 × 10 × 10)

Volume = 100 × 10

Volume = 1000 cu. cm

Now

1/4 is filled.

So,

1/4 × Volume

1/4 × 1000

250 cu. cm