Question

A cubical box of edge 2 cm and of mass 5 kg is kept on a table top. Calculate-
1) the thrust of the block on the table top.
2)the pressure of the block on the table top.

Answer 1

Physics

⛄HERE IS YOUR ANSWER.⛄

⏩Edge = Side = 2 cm =

$\frac{2}{100}$

= 0.02m.

Now, 1) Thrust = mg = 5× 9.8 = 49 N

2) Pressure =

$\frac{thrust}{area}$
=
$\frac{49}{(0.02) \times (0.02 \times 0.02)}$

= 1,22,500 N/m²

= 1.225 × 10^5 N/m² or Pa.

⛄HOPE IT HELPS.⛄

Answer 2

thrust 5 kg and pressure =thrust/area=5/2=2.5 Pa