Question

a cubical box of side 12cm has a hemispherical dome like structure on its top having max diameter find the total surface area of the solid

Answer 1

hii mate!!

R=6 cm
TSA of cube=6*12*12
                    =144*6
                    =864 sq.cm
TSA of hemisphere=3*22/7*6*6
                               =339.43 sq.cm 
TSA of solid=864+339.43
                    =1203.43 sq.cm

hope it helps!!☺☺☺☺

Answer 2

Answer:

Answer:

977.2 $cm^{2}$

Step-by-step explanation:

Cube

a = 12 cm

Hemisphere

r = $\frac{12}{2}$ cm

 = 6 cm

The solid is made up of cube and hemisphere, with the base of the hemisphere partially covering one side leaving four corners of the side and the rest three sides bare. To find the Total Surface Area (T.S.A) we have the area the objects visible to us.

∴ T.S.A of the solid = C.S.A of hemisphere + T.S.A of cube - Area of the base  

                                   of the hemisphere  

                                = 2π$r^{2}$ + 6$a^{2}$ - π$r^{2}$

                                = π$r^{2}$ + 6$a^{2}$

                                = $\frac{22}{7}$ × $6^{2}$ + 6 × $12^{2}$

                                = 113.14 + 864

                                = 977.14 $cm^{2}$