Math, asked by Vandanash1511, 5 months ago

A cubical box with lid has a length of 30 cm. Find the cost of
painting the inside
and outside of the box at 5.50 per m².
Two cubes of side 4 cm are fixed together. Find the total surface area of the new
solid formed.
0540
90,00 QT
30
30
60

Answers

Answered by baidsweta98
0

A cubical box with lid has a length of 30 cm. Find the cost of painting the hids and outside of the box at 5.50 per m2

We have to find the surface area of the cubical box.

Surface area of the cube = 6a² where a = 30 cm

⇒ 6*30*30

⇒ 5400 sq cm

As the cubical box has to be painted both from the outside and inside.

So, the total surface area = Inner surface area + outer surface area

⇒ 5400 + 5400

= 10800 sq cm

As we know that 1 sq m = 10000 sq cm

Surface area in sq m = 10800/10000

Surface area in sq m = 1.08 sq m

Cost of painting the cubical box = Rs. 5.50 per sq m

Total cost of painting = 5.5*1.08

Total cost = Rs. 5.94

So, the total cost of painting the cubical box from outside and inside is 5.94

Answered by RheaBenjamin
1

Answer:

We have to find the surface area of the cubical box.

Surface area of the cube = 6a² where a = 30 cm

⇒ 6*30*30

⇒ 5400 sq cm

As the cubical box has to be painted both from the outside and inside.

So, the total surface area = Inner surface area + outer surface area

⇒ 5400 + 5400

= 10800 sq cm

As we know that 1 sq m = 10000 sq cm

Surface area in sq m = 10800/10000

Surface area in sq m = 1.08 sq m

Cost of painting the cubical box = Rs. 5.50 per sq m

Total cost of painting = 5.5*1.08

Total cost = Rs. 5.94

So, the total cost of painting the cubical box from outside and inside is 5.94

Step-by-step explanation:

I hope it helped you...

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